1 solutions
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0
m , n = map(int,input().split(' ')) dic = {} for i in range(m,n+1): for j in str(i): dic[j] = dic.get(j,0) +1 for i in range(10): if str(i) not in dic: dic[str(i)] = 0 dic = sorted(dic.items(),key=lambda x:x[0]) lst =[] for i in dic: lst.append(str(i[1])) print(' '.join(lst))
Information
- ID
- 568
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 8
- Accepted
- 1
- Uploaded By