1 solutions
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0
lst2 = [] lst3 = [] lst1 =[] for i in range(2): if i == 0: x = input().split() for j in x: lst1.append(int(j)) lst1 = sorted(lst1) else: number = input() for i in number: lst2.append(i) for i in lst2: if i == 'A' : lst3.append(lst1[0]) if i == 'B' : lst3.append(lst1[1]) if i == 'C': lst3.append(lst1[2]) for i ,j in enumerate(lst3): lst3[i] = str(j) output = ' '.join(lst3) print(output)
Information
- ID
- 534
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- # Submissions
- 12
- Accepted
- 3
- Uploaded By